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NCERT Solutions for Class 10 Maths Chapter 6 Triangles

Question 1. Then, A BD. Question 2. The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is A 9 cm B 10 cm C 8 cm D 20 cm Solution: B We know that the diagonals of a rhombus are perpendicular bisectors of each.

Question 3. FD B AB. Ncerrt C BC. EF D BC. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question Is the triangle with sides 25 cm, 5 cm and 24 cm a right 10th ncert 6.6 50 Give reasons for your answer. Solution: False We know that, if two triangles 10th ncert 6.6 50 similar, then their corresponding angles are equal. Is the following statement true? Solution: False Two quadrilaterals are similar nncert their corresponding angles are equal and corresponding sides must also be proportional.

Two sides and the perimeter of one triangle are respectively three times the corresponding sides and the perimeter of the other triangle. Are the two triangles similar? Solution: True Here, the corresponding 10th Ncert 6.6 two sides and the perimeters of two triangles are proportional, then the third side of both triangles will also in proportion.

If in two right triangles, one of the acute angles hcert one triangle is equal to an acute angle of the other triangle, can you say that the two triangles will be 10th ncert 6.6 50 Is it true to say that if in two triangles, an angle of one triangle is equal to an angle of another triangle and two sides of one triangle are proportional to the two sides of the other triangle, then the triangles are similar?

Solution: False 10th ncert 6.6 50, according to SAS similarity criterion, if one angle of a triangle is equal to an angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar. Here, one angle and two sides of two triangles are equal but these sides not including equal angle, so given statement is not correct. AP Hence proved. Find the altitude of an equilateral triangle of side 8 cm.

Solution: Let ABC be an 10th ncert 6.6 50 triangle 10th ncert 6.6 50 side 8 cm i. Then, D is the mid-point of BC. Corresponding sides of two similar triangles are in the ratio of 2 : 3.

If the area of the smaller triangle is 48 cm 2find the area of the larger triangle. If PN. Areas of two similar triangles are 36 cm 2 and cm 2. If the length of a side of the larger triangle is 20 cm, find the length of the corresponding side of the smaller triangle. A 15 metres high tower casts a shadow 24 metres long at a certain time and at the 10th ncert 6.6 50 time, a telephone pole 10th ncert 6.6 50 a shadow 16 metres long.

Find the height of the 110th pole. Hence, the height of the point on the wall 10th ncert 6.6 50 the top of the ladder reaches is 8 m. Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. 10th ncert 6.6 50 the 10th ncert 6.6 50 of the point on ncrt wall where the top of the ladder reaches. The top of the ladder reached to A and distance of ladder from the base of the wall BC is 6 m.

Find the lengths of the remaining sides of the triangles. Prove that if a line is drawn parallel to one side of a triangle to intersect the other two sides, then the two nfert are divided in the same ratio. To prove : DE divides the two sides in the same ratio. Also AB PS. Hence proved. A 5 m long ladder is placed leaning towards a vertical wall 10th ncert 6.6 50 that it reaches the wall at 10th ncert 6.6 50 point 4 m high. If the foot of the ladder is moved 1.

It is proposed to construct a 26 km highway which directly connects the two cities 10gh and B. Find how much distance will be saved in reaching city B from city A after the construction of the highway.

A flag pole nccert m high casts a shadow 9. Find the distance of the top of the pole from the far end 10th Ncert 6.6 Zip Code of the shadow.

The distance of the top of the pole, C from the far end i. A street light bulb is fixed on a pole 6 m above the level of the street. If a woman of height 1.

Let distance between pole and woman be x m. Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.

Prove that the area of the equilateral triangle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the equilateral triangles drawn on the other two sides of the triangle. Hence proved Question 5. RD Sharma Class 12 Solutions. Watch Youtube Videos.

Concurrency: Concurrency is a special type of numerical that you will come across while solving the problems of the exercise of the triangle. You can Ncert Solutions Class 10th Maths Ch 7 Test expect many sums to be present that are related to each type of triangle. Watch Youtube Videos. Solution: Question Here are the types of the triangle and the notes about them:. Sample Papers Practice and Board Papers. Find each of its altitudes.
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