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Exercise | Chapter 1 Polynomials, Class 10, Maths, NCERT Solutions

These solutions for Straight Lines are extremely popular among Class 11 Science students for Math Straight Lines Solutions come handy for quickly completing your homework and preparing for exams. Draw a quadrilateral in the Cartesian plane, whose vertices are �4, 50, 75, �5 and �4, �2. Also, find its area. Thus, area ABCD. The base of an equilateral triangle with side 2 a lies along they y -axis such that the mid point of the base is at the origin.

Find vertices of the triangle. Assume that base BC lies along the y -axis such that the mid-point of BC is at the origin. Now, it is clear that 10th ncert of math 211 coordinates of point C are 0, awhile the coordinates of point B are 0, � a. It is known that the line joining a vertex of an equilateral triangle with the mid-point of its opposite side is perpendicular. Thus, the vertices of the given equilateral triangle are 0, a0, � aand or 0, a0, � a.

Find the distance between and when: i PQ is parallel to the y -axis, ii PQ is parallel to the x -axis. The given points are. In this case, distance between P and Q. Find a point on the x -axis, which is equidistant from the points 7, 6 and 3, 4. Let a0 be the point on the x axis that is equidistant from the points 7, 6 10th ncert of math 211 3, 4. Thus, the required point on the x -axis is. It is known that the s lope m of a non-vertical line passing through the points x 1y 1 and x 2y 2 is given by.

Hence, the required slope of the line is. Without using the Pythagoras theorem, show that the points 4, 410th ncert of math 211, 5 and �1, �1 are the vertices of a right angled triangle. Slope of BC m 2. Slope of CA Lorem lpsum 302 boatplans/cruise/cincinnati-sightseeing-cruise-with ���-������ cincinnati sightseeing cruise with ���������� 3.

Thus, the points 4, 43, 5and �1, �1 are the vertices Ncert Book For Class 10th Maths Mac of a right-angled triangle. 10th ncert of math 211 the value of x for which the points x�12, 1 and 4, 5 are collinear.

Without using distance formula, show that points �2, �14, 03, 3. Let points �2, �14, 03, 3and �3, 2 be respectively denoted by A, B, C, and D. Slope of AB. Therefore, both pairs of opposite sides of quadrilateral ABCD are parallel.

Hence, ABCD is a parallelogram. Thus, points �2, �14, 03, 3and �3, 2 are the vertices of a parallelogram. Find the angle between the x -axis and the line joining the points 3, �1 and 4, �2. The slope of the line joining the points 3, �1 and 4, �2 is. The slope of a line is double of the slope of another line. If tangent of the angle between them isfind the slopes of he lines. Let be the slopes of the two given lines such. It is given that the tangent of the angle between the two lines is.

Hence, the slopes of the lines are �1 and �2 Lorem lpsum 302 boatplans/fishing-boats-sale/endeavour-500-fishing-boats-for-sale-linkedin just click for source and �1 or 1 and 2 or. A line passes. If slope of the line is mshow.

The slope of the line passing through is. If three point h, 0 10th ncert of math 211, a, b and 0k lie on a line, show. Consider the given population and year graph. Find the slope of the line AB and using it, find what will be the population in the year ? Since line AB passes through points A92 and B97its slope is. Let y be the population in the year Then, according 10th ncert of math 211 the given graph, line AB must pass through point Cy.

Thus, the slope of line AB iswhile in the yearthe population will be Find the equation of the line which passes through the point �4, 3 with slope. We know that the equation of the line passing 10th ncert of math 211 pointwhose slope is mis. Thus, the equation of the line passing through point �4, 3whose slope isis. Find the equation of the line which intersects the x -axis at a distance of 3 units to the left of origin with slope �2.

It is known that if a line with slope m makes x- intercept dthen the equation of the line is Lorem lpsum 302 boatplans/small-boats/small-boat-sailing-vessel-size continue reading as.

It is known that if a line with slope m makes y- intercept cthen the equation of the line is given as. Find the equation of the line which passes through the points �1, 1 and 2, �4. It is known that the equation of the line passing through points x 1y 1 and x 2y 2 is. Find equation of the median through the vertex R. By mid-point formula, the coordinates of point L are given by.

Thus, the required equation of the median through vertex R is. Find the equation of 10th ncert of math 211 line passing through �3, 5 and perpendicular to the line through the points 2, 5 and �3, 6. The slope of the line joining the points 2, 5 and �3, 6 is. We know that two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each.

Therefore, slope Class 10th Ka Ncert Book Math 20 of the line perpendicular to the line through the Lorem lpsum 302 boatplans/boat-trailer/aluminum-boat-trailer-rims-youtube aluminum trailer rims youtube 2, 5 and �3, 6.

A line perpendicular to the line segment joining the points 1, 0 and 2, 3 divides it in the ratio 1: n. Find the equation of Lorem lpsum 302 boatplans/boats-models/large-rc-boat-models-quote continue reading line.

According to the section formula, the coordinates of the point that divides the line segment joining the points 1, 0 and 2, 3 in the ratio 1: n is given by. Therefore, slope of the line that is perpendicular to the line joining the points 1, 0 and 2, 3.

Now, the equation of the line passing through and whose slope is is given by. Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point 2, 3.

It is given that the line cuts off equal intercepts on both the axes. Find equation of the line passing through the point 2, 2 and cutting off intercepts on the axes whose sum is 9. Find equation of the line through the point 0, 2 making an angle with the positive x -axis. Also, find the equation of line parallel to it and crossing the y -axis at a distance of 2 units below the origin.

The slope of the line making an angle with the positive x -axis is. Now, the equation of the line passing through point 0, 2 and having a slope is.

The slope of line parallel to line is. It is given that the line parallel to line crosses the y -axis 2 units below the origin i. Hence, the equation of the line passing through point 0, �2 and having a slope is. The perpendicular from the origin to a line meets 10th ncert of math 211 at the point � 2, 9find the equation of the line.

The slope of the line joining the origin 0, 0 and point �2, 9 is. Accordingly, the slope of the line perpendicular to the line joining the Lorem lpsum 302 boatplans/chapter/ice-fishing-boots-on-sale-quiz http://myboat302 boatplans/chapter/ice-fishing-boots-on-sale-quiz.html and point � 2, 9 is.

Now, the equation of the line passing through point �2, 9 and having a slope m 2 is. The length L in centimetre of a copper rod is a linear function of its Celsius temperature C. Accordingly, points 20, Lorem lpsum 302 boatplans/boat-kits/gondola-model-boat-kits-apk Article source, assuming C along the x -axis and L along the y -axis, we have two points i.

Therefore, the linear relation Lorem lpsum 302 boatplans/boats/boat-tours-ocean-city-maryland-yoga continue reading L and C is the equation of the line passing through points 20, L � Assuming selling price per litre along the x -axis and demand along the y -axis, we have two points i. Therefore, the linear relationship between selling price per litre and demand is the equation of the line passing through points 14, and 16, P a, b is the mid-point of a line segment between axes.

Show that equation of the line is. Let AB 10th ncert of math 211 the line segment between the axes and let P ab be its mid-point. Thus,the equation of the line is. Point R h, k divides a line segment between the axes in the ratio Find equation of the line. Since point R hk divides AB in the ratio 1: 2, according to the section formula.

Therefore, the respective coordinates of A and B are and 0, 3 k. Now, the equation of line AB passing through points.

In order to show that points 3, 010th ncert of math 211, �2and 8, 2 are collinear, it suffices to show Ncert Solutions Of Class 10th Maths Chapter 7 20 that the line passing through points 3, 0 and �2, �2 also passes through point 8, 2.

Therefore, the line passing Lorem lpsum 302 boatplans/ncert-solutions-class/catamaran-manufacturers-thailand-open visit web page points 3, 0 and �2, �2 also passes through point 8, 2. Hence, points 3, 0 10th ncert of math 211, �2, �2and 8, 2 are collinear.

Set Password. To practice and easily revise problems related to trigonometry ratios, trigonometric identities and ratio of complementary angles use solutions for Chapter 8 of Class 10 Maths. These solutions help you to revise and practice with the easiest methods provided by our experts. You can ask any questions across topics and our experts will get in touch with you within 24 hours. It also explains the factorization method of solving quadratic equations and the square method. The third Exercise has questions on division of polynomials. CBSE focuses on all-round development of Class 10 students to prepare them for their further education.
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