Ncert Solutions Class 10 Maths Ch 6 Ex 6.2 Online,Wooden Kitchen Toys Asda Yupoo,Doral Boats Models Zip Codes,Yachts & Boats Trading Dmcc App - PDF Books
28.01.2021, adminThese ncert book chapter wise questions and answers are very helpful for CBSE board exam. Show that the function given by is strictly increasing on R.
Therefore, is strictly increasing on Ncert Solutions For Class 10 Maths Ch 6 Ex 6.2 China R. Therefore, is strictly increasing in. Therefore, is strictly decreasing in. Therefore, is neither increasing nor decreasing in. Therefore, we have two intervals. Therefore, we have sub-intervals are. For interval taking sayfrom eq. Hence, a is strictly increasing in. Therefore, we have two sub-intervals. Therefore, is strictly decreasing. Therefore, is strictly increasing. Therefore, we have three disjoint intervals.
For intervalfrom eq. For interval. Here, factors and are non-negative for all. Therefore, is strictly increasing if. And is strictly decreasing if. Hence, is strictly increasing in and is strictly decreasing in. Domain of the given function is given to be.
Also. From eq. Ncert solutions class 10 maths ch 6 ex 6.2 online, we. For taking say. Since and we have. Hence, is an increasing function of in. Therefore, is strictly increasing on. Since in. Therefore, is strictly decreasing on. Hence, is neither strictly increasing not strictly decreasing on.
A On 0, 1. And. Therefore, is strictly increasing on 0, 1. B For. For is in second quadrant and hence is negative and between and 0. On 1, 2. Minimum value of is and maximum value is. Therefore least value of is. Here for every either or. And forsay. On the interval i. Therefore, is increasing on R. In option Dfor all in the interval 0, 2. Ncert solution class ncert solutions class 10 maths ch 6 ex 6.2 online Maths includes text book solutions from both part 1 and part 2.
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The second question consists of a triangle having sides PQ and QR, respectively. The measurements of the sides are provided. Following this, the students need to find out whether EF QR. The question can again be solved using properties of similar triangles. If the ratios of sides are similar, then, they are parallel to each other. Else, they are not. They can easily do this by the basic proportionality theorem.
This question is quite similar to the previous one. The students can solve this in three steps by the properties of similarity of triangles. Both these questions in the exercise are based on the same concept of basic proportionality theorem and similarity of triangles. Some parallel conditions are given, and students need to prove that one of the lines in the triangle is parallel to the base of the triangle.
Use the concepts wisely to prove the given questions. While solving this question, the students need to recall the concept of mid-point theorem they learnt in Class 9.
The question can easily be solved by combining both the mid-point theorem and the basic proportionality theorem. This can be solved using theorem 6. This question is Class 10 Maths Ncert Solutions Ch 6 Exercise 6.2 Pdf a little tricky.
The students have to prove that in the given trapezium, the point at which diagonals intersect are divided in the same ratio. For this, the students must be well aware of the properties of trapezium as well as the triangle. Following this; they can use the basic proportionality theorem to prove the question. Similarly questions 7, 8, 9 and 10 can be solved by using Thales as well as its converse. Question number 10 can be solved on the basis of similarity also, which will we study in Exercise 6.
Basic Proportionality Theorem: If a line is drawn parallel to one side of a triangle to intersect the other sides in distinct points, the other two sides are divided in the same ratio.
The converse of the Thales theorem is also important to solve the questions. We are here to help you in education. Never hesitate to take help from us. Just mail or message us about to what do you need.
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