10th Ncert Important Questions Difference,Sdt Questions In Compiler Design Zipper,Class 5 Math Chapter 11 Question Answer Free - Step 1
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The 4 th term of an A. Prove that the 25th term of the A. The 7 th term of an A. Find the A. Find 10th term from end of the A. Find how many two-digit numbers are divisible by 6? How many natural numbers are there between and , which are divisible by 7? How many two-digit numbers are divisible by 3? How many three-digit natural numbers are divisible by 7? Find the number of all three-digit natural numbers which are divisible by 9. Find the number of natural numbers between and which are divisible by both 2 and 5.
Find the middle term of the A. Let a and d be the first term and common difference of A. How many terms of the A. Find the sum of the first 25 terms of an A. The first and the last terms of an AP are 5 and 45 respectively. If the sum of all its terms is , find its common difference. The first and the last terms of an AP are 8 10th Ncert Important Questions Use and 65 respectively. Find the sum of all three digit natural numbers, which are multiples of Which term of the A. Determine the A. The 19th term of an AP is equal to three times its 6 th term.
If its 9 th term is 19, find the A. The 9th term of an A. If its 5 th term is 22, find the A. The sum of the 5th and the 9th terms of an AP is If its 25 th term is three times its 8 th term, find the AP. Find the value of the middle term of the following A.
The 14 th term of an AP is twice its g th term. If its 6 th term is -8, then find the sum of its first 20 terms. The 13th term of an AP is four times its 3rd term.
If its fifth term is 16, then find the sum of its first ten terms. If the sum of first 7 terms of an A. P is 49 and that of its first 17 terms is , find the sum of first n terms of the 10th Ncert Important Questions View A. The first term of an A. Find the number of terms and the common difference of the A. The n th term of 10th Ncert Important Questions Korean an A. Find the sum of first 20 terms of this A. Find the 25 th term of this AP. The sum of the first seven terms of an AP is If its 4 th and the 17 th terms are in the ratio 1 : 5, find the AP.
Covering whole maths book is not an easy task. So, We should prepare in a strategic manner. We should start preparing using ncert books and understand which chapters are more important. It will give you a clear picture of what you should cover first. Once you have decided and ranked Maths chapters according to their importance.
Now, It time to jump into chapters. We should focus on the important concepts and important chapters. Ex: 1. Ex No 1,2,3,4,7,8 Section formula. Q 2,5,10,12,13,14,15,16 05 Circles Tangents to a circle Q3 Ex The bond between two atoms formed by sharing of two pairs of electrons is called a double bond.
Examples: i Formation of Oxygen atom has six electrons in its outermost shell, two short of forming a complete octet. Thus each oxygen atom in O2 shares 2 electrons with the other oxygen atom attain stable configuration. The bond formed between two atoms through the sharing of three electron pairs is called a triple bond. Examples: i Formation of N2 molecules: Nitrogen atoms have five electrons in their outermost shells.
Therefore, in N2 molecules two nitrogen atom shares 3 electrons with each other, Thus acquiring the stable structure and forming a N2 molecule with triple bond. The covalent compound is said to be formed when two atoms achieve stability by the sharing of electron pair, each contributing one electron to the electron pair.
In this way the atom can be regarded as having acquired a noble gas configuration. Covalent compound exhibit the following properties: i These have low melting and boiling point. They are non-electrolyte. Covalent compounds have strong bonds within the molecule and intermolecular force are very weak and so have low melting and boiling points. Covalent compound are formed due to sharing of electron between atoms and no charged particle are formed, hence such compound is generally bad conductor of electricity.
Elements of stable configuration exist in atomic form. For example, inert gases He, Ne, Ar, etc. Elements which are short of inert configuration by 1,2 or 3 electron shell contain 5, 6, 7 electrons achieve stable configuration by sharing requisite number of electron with other atoms and exist in molecular form.
For example, chlorine atom has 7 electrons in their outermost shell, thus two Cl atoms share one electron of each other and exist as Cl-Cl Cl2. When an element possesses two or more different crystalline forms in the same state they are called allotropes and the phenomenon is known as allotropy. Diamond and graphite are the two allotropes of carbon. They are chemically identical when equal quantities of diamond and graphite are burnt both of these produce the same amount of carbon dioxide.
However, as they exist in different form in the solid state, they have entirely different physical properties. Carbon has two unique features: i It is tetravalent. Because of tetra-valency carbon atom in its compound are linked by single, double or triple bonds. Carbon atom are also bonded with oxygen, hydrogen, chlorine, nitrogen and sulphur giving rise to compounds with specific properties typical of the element other than carbon present in the molecule.
Saturated hydrocarbons: A hydrocarbon in which each carbon atom is attached to four other atoms is known as saturated hydrocarbon. The bonds so formed are single covalent bonds. These hydrocarbons are also called alkanes. Carbon atom has a small size and this enables its nucleus to hold on the shared pair of electron quite strongly. This is why carbon forms strong bond with most other elements and the compounds formed are exceptionally stable as compared to covalent bond formed by other elements.
The unique property of carbon to form bonds with other carbon atom giving rise to large molecules is called catenation. Due to catenation compounds of carbon have long chain of carbon and even carbon atoms arranged in rings. Saturated hydrocarbon- methane CH4 , ethane C2H6. Unsaturated hydrocarbon- ethane C2H4 , ethyne C2H2. Hydrocarbon can be classified either on the basis of nature of bonds or nature of chains between carbon atoms.
Example CH4 methane. Example C2H4 ethene. Example: butane and isobutene. Example: Cyclohexane and benzene. Silicon forms compound which have chains like carbon. Compound formed by silicon are few and are not so reactive.
We first write the carbon atoms joined together in a chain and then fill the remaining valences with hydrocarbon atoms. In this way we get following structures for saturate hydrocarbon having 3,4,5 and 6 carbon atoms respectively. Then name these according to the number of carbon atoms example propane, butane, pentane and hexane for saturate hydrocarbon containing 3,4,5 and 6 carbon atoms respectively. The group formed by removal of the hydrogen atom from an alkane molecule is called an alkyl radical or alkyl group.
For example, if hydrogen is removed from methane, it is �CH3 methyl group. The molecular formula for an alkane 4 carbon atom is C4H An alkene contains 2 hydrogen atom less than the corresponding alkane and an alkyne contain 4 hydrogen atom less than corresponding alkanes. Therefore, molecular formula of i alkene is C4H8 ii alkyne is C4H6.
The compound having a triple bond is called an alkyne. It has 4 hydrogen atom less than the corresponding alkane. Therefore, C3H4 is an alkyne. Its corresponding alkane is C3H8. A group which determines the chemical nature of an organic compound is called a functional group. A homologous series in a group or family of compounds which contain the same functional group but have different chains lengths thus these have the same chemical properties but different physical properties but different physical properties that vary in a regular manner.
Characteristics of homologous series i It has a general formula in term of number of carbon atoms. Since an alkene contain two hydrogen atom less than the corresponding alkane, therefore the general formula for alkenes is CnH2n.
Further since an alkyne contain 2 hydrogen atoms less than the corresponding alkene hence the general formula for alkynes is CnH2n Two successive homologous should differ: i by 14 in molecular mass and ii one carbon atom and two hydrogen atom in terms of atoms in their molecules.
The phenomenon in which two or more compounds having same molecular formula may exist with different structural formulae is called isomerism. The compound that contain the same molecular formula but different structures are called structural isomers.
The isomers of a compound have same chemical properties and different physical properties. For example, a four carbon atom saturated hydrocarbon C4H10 is called butane and a-5c atom straight saturated hydrocarbon is called pentane C5H Branched chain saturated hydrocarbon: The following rule should be followed for naming branched chain saturated carbon.
The compound is then named on the basis of number of carbon atoms present in the longest chain. This is called parent hydrocarbon. That is, the terminal carbon atom which is nearest to the carbon atom containing an alkyl group or a substituent is given number 1.
Hydrocarbons containing functional groups: In case a functional group is present, it is indicated in the name of the compound with a prefix for halides and a suffix for other functional groups. If the name is to be given by a prefix, then halo chloro, bromo, iodo is written before the name of the corresponding hydrocarbon, e. Therefore, ending ene- is to be used. Therefore, the compound is propane. When the carbon atoms are numbered from left hand side, the double bond appears between carbon 2 and 3.
When the carbon atoms are numbered from the right hand side, the double bond appears between carbon atom 1 and carbon atom 2.
Since we have to name it in such a way that the carbon joined by a double bond carries the lowest possible numbers.
The concept of functional group is important in organic chemistry for the following reasons: i Functional groups are taken as the basis for naming of the organic compounds. Compounds containing the same functional group show similar chemical behavior. Common name: Ethylidene dibromide. IUPAC name: 1, 1 dibromo ethane.
Out of these only carboxylic acids would turn blue litmus solution red. The hydroxyl group -OH when present in aliphatic organic compounds is known as an alcoholic group.
The corresponding compound is an alcohol. This is because in these cases gaseous substance burn. Carboxylic acids containing long chain of carbon atoms are fatty acids. They are use as mild acids in foods, cold drinks, drugs, perfumes and are chief constituents of washing soaps. Combustion is the burning of compounds in air to give CO2 and water with the liberation of heat and light.
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